WebJul 18, 2008 · I simply want to select the Acuity value from the row with the maximum date per account number. So my results should look like the following: Account Acuity 6468604 Routine - Level 2 6468700 Critical - Level 4 6468742 Routine - Level 2 This will be a derived table in a much larger query. Thanks for your help! Monday, August 11, 2008 7:01 PM … WebOct 1, 2024 · To get the max date im using the following: select id, Parent, Date From Table T1 Where Date = (select Max (Date) from Table T2 where T1.id= T2.id ) Wich works fine for the id = 1 But for the id = 3 it's not working The result is : 1 Alex 2024-10-01 00:00:00.0000000 Any ideas Why? sql-server sql-server-2008 t-sql Share Improve this …
Date Functions in SQL Server and MySQL - W3School
WebOct 20, 2015 · Solution 1 The first solution is the following: SELECT ID, (SELECT MAX(LastUpdateDate) FROM (VALUES (UpdateByApp1Date), (UpdateByApp2Date), (UpdateByApp3Date)) AS UpdateDate(LastUpdateDate)) AS LastUpdateDate FROM ##TestTable Solution 2 We can accomplish this task by using UNPIVOT: WebIf you need to group or summarize the data, turn the select query into a totals query. You can then use an aggregate function, such as Max or Min to return the highest or lowest value, … dynamix growth fund
Date Functions in SQL Server and MySQL - W3School
WebHere is the syntax of the MAX () function: MAX (expression) Code language: SQL (Structured Query Language) (sql) The MAX () function returns the highest value in a set. If the set is empty, the MAX () function returns NULL. Note that the MAX () function ignores NULL values. Db2 MAX () function examples WebMar 3, 2024 · Altering the query to include a subquery with MAX on record id, results with student latest GPA data. SELECT s.id, s.first, s.last, sd.school_year, sd.gpa FROM Student s LEFT OUTER JOIN StudentGrades sd ON s.id=sd.student_id AND sd.record_id = (SELECT MAX(record_id) FROM StudentGrades WHERE student_id=sd.student_id) WebFeb 11, 2024 · 2 Answers Sorted by: 1 Use a window function: select id, work from ( select id, work, row_number () over (order by work) as rn from x ) t where rn = 1 -- or 2 or 3 ... If you need to deal with duplicate dates, use dense_rank () instead of row_number () and use a second window function to provided numbers for each date: cs4ri